Integrand size = 24, antiderivative size = 165 \[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\frac {40}{567} x \sqrt [4]{-1+3 x^2}+\frac {2}{63} x^3 \sqrt [4]{-1+3 x^2}+\frac {2}{27} \sqrt {\frac {2}{3}} \arctan \left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac {2}{27} \sqrt {\frac {2}{3}} \text {arctanh}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )+\frac {40 \sqrt {\frac {x^2}{\left (1+\sqrt {-1+3 x^2}\right )^2}} \left (1+\sqrt {-1+3 x^2}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\sqrt [4]{-1+3 x^2}\right ),\frac {1}{2}\right )}{567 \sqrt {3} x} \]
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Time = 0.12 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.00, number of steps used = 15, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {454, 240, 226, 327, 409, 453} \[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\frac {2}{27} \sqrt {\frac {2}{3}} \arctan \left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{3 x^2-1}}\right )+\frac {40 \sqrt {\frac {x^2}{\left (\sqrt {3 x^2-1}+1\right )^2}} \left (\sqrt {3 x^2-1}+1\right ) \operatorname {EllipticF}\left (2 \arctan \left (\sqrt [4]{3 x^2-1}\right ),\frac {1}{2}\right )}{567 \sqrt {3} x}-\frac {2}{27} \sqrt {\frac {2}{3}} \text {arctanh}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{3 x^2-1}}\right )+\frac {40}{567} \sqrt [4]{3 x^2-1} x+\frac {2}{63} \sqrt [4]{3 x^2-1} x^3 \]
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Rule 226
Rule 240
Rule 327
Rule 409
Rule 453
Rule 454
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {4}{27 \left (-1+3 x^2\right )^{3/4}}+\frac {2 x^2}{9 \left (-1+3 x^2\right )^{3/4}}+\frac {x^4}{3 \left (-1+3 x^2\right )^{3/4}}+\frac {8}{27 \left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}}\right ) \, dx \\ & = \frac {4}{27} \int \frac {1}{\left (-1+3 x^2\right )^{3/4}} \, dx+\frac {2}{9} \int \frac {x^2}{\left (-1+3 x^2\right )^{3/4}} \, dx+\frac {8}{27} \int \frac {1}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx+\frac {1}{3} \int \frac {x^4}{\left (-1+3 x^2\right )^{3/4}} \, dx \\ & = \frac {4}{81} x \sqrt [4]{-1+3 x^2}+\frac {2}{63} x^3 \sqrt [4]{-1+3 x^2}+\frac {4}{81} \int \frac {1}{\left (-1+3 x^2\right )^{3/4}} \, dx+\frac {2}{21} \int \frac {x^2}{\left (-1+3 x^2\right )^{3/4}} \, dx-\frac {4}{27} \int \frac {1}{\left (-1+3 x^2\right )^{3/4}} \, dx+\frac {4}{9} \int \frac {x^2}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx+\frac {\left (8 \sqrt {x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{27 \sqrt {3} x} \\ & = \frac {40}{567} x \sqrt [4]{-1+3 x^2}+\frac {2}{63} x^3 \sqrt [4]{-1+3 x^2}+\frac {2}{27} \sqrt {\frac {2}{3}} \tan ^{-1}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac {2}{27} \sqrt {\frac {2}{3}} \tanh ^{-1}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )+\frac {4 \sqrt {\frac {x^2}{\left (1+\sqrt {-1+3 x^2}\right )^2}} \left (1+\sqrt {-1+3 x^2}\right ) F\left (2 \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )|\frac {1}{2}\right )}{27 \sqrt {3} x}+\frac {4}{189} \int \frac {1}{\left (-1+3 x^2\right )^{3/4}} \, dx+\frac {\left (8 \sqrt {x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{81 \sqrt {3} x}-\frac {\left (8 \sqrt {x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{27 \sqrt {3} x} \\ & = \frac {40}{567} x \sqrt [4]{-1+3 x^2}+\frac {2}{63} x^3 \sqrt [4]{-1+3 x^2}+\frac {2}{27} \sqrt {\frac {2}{3}} \tan ^{-1}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac {2}{27} \sqrt {\frac {2}{3}} \tanh ^{-1}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )+\frac {4 \sqrt {\frac {x^2}{\left (1+\sqrt {-1+3 x^2}\right )^2}} \left (1+\sqrt {-1+3 x^2}\right ) F\left (2 \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )|\frac {1}{2}\right )}{81 \sqrt {3} x}+\frac {\left (8 \sqrt {x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{189 \sqrt {3} x} \\ & = \frac {40}{567} x \sqrt [4]{-1+3 x^2}+\frac {2}{63} x^3 \sqrt [4]{-1+3 x^2}+\frac {2}{27} \sqrt {\frac {2}{3}} \tan ^{-1}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac {2}{27} \sqrt {\frac {2}{3}} \tanh ^{-1}\left (\frac {\sqrt {\frac {3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )+\frac {40 \sqrt {\frac {x^2}{\left (1+\sqrt {-1+3 x^2}\right )^2}} \left (1+\sqrt {-1+3 x^2}\right ) F\left (2 \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )|\frac {1}{2}\right )}{567 \sqrt {3} x} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 6.07 (sec) , antiderivative size = 184, normalized size of antiderivative = 1.12 \[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\frac {2 x \left (-20+51 x^2+27 x^4-31 x^2 \left (1-3 x^2\right )^{3/4} \operatorname {AppellF1}\left (\frac {3}{2},\frac {3}{4},1,\frac {5}{2},3 x^2,\frac {3 x^2}{2}\right )-\frac {80 \operatorname {AppellF1}\left (\frac {1}{2},\frac {3}{4},1,\frac {3}{2},3 x^2,\frac {3 x^2}{2}\right )}{\left (-2+3 x^2\right ) \left (2 \operatorname {AppellF1}\left (\frac {1}{2},\frac {3}{4},1,\frac {3}{2},3 x^2,\frac {3 x^2}{2}\right )+x^2 \left (2 \operatorname {AppellF1}\left (\frac {3}{2},\frac {3}{4},2,\frac {5}{2},3 x^2,\frac {3 x^2}{2}\right )+3 \operatorname {AppellF1}\left (\frac {3}{2},\frac {7}{4},1,\frac {5}{2},3 x^2,\frac {3 x^2}{2}\right )\right )\right )}\right )}{567 \left (-1+3 x^2\right )^{3/4}} \]
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\[\int \frac {x^{6}}{\left (3 x^{2}-2\right ) \left (3 x^{2}-1\right )^{\frac {3}{4}}}d x\]
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\[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\int { \frac {x^{6}}{{\left (3 \, x^{2} - 1\right )}^{\frac {3}{4}} {\left (3 \, x^{2} - 2\right )}} \,d x } \]
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\[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\int \frac {x^{6}}{\left (3 x^{2} - 2\right ) \left (3 x^{2} - 1\right )^{\frac {3}{4}}}\, dx \]
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\[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\int { \frac {x^{6}}{{\left (3 \, x^{2} - 1\right )}^{\frac {3}{4}} {\left (3 \, x^{2} - 2\right )}} \,d x } \]
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\[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\int { \frac {x^{6}}{{\left (3 \, x^{2} - 1\right )}^{\frac {3}{4}} {\left (3 \, x^{2} - 2\right )}} \,d x } \]
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Timed out. \[ \int \frac {x^6}{\left (-2+3 x^2\right ) \left (-1+3 x^2\right )^{3/4}} \, dx=\int \frac {x^6}{{\left (3\,x^2-1\right )}^{3/4}\,\left (3\,x^2-2\right )} \,d x \]
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